Problem 1
- Test level
- Multiple choice
- No calculator
- 4 pts
What is the real domain of ?
Answer
, since and .
Full solution
The square root requires , giving .
The denominator separately excludes one, even though the square root is defined there.
Intersect the two conditions. Negative two is included because its numerator is zero and denominator is nonzero.
Where students lose points
Combine domain conditions with and, rather than choosing just one restriction.

